Question

Calculate the concentration of a solution of glucose which is isotonic at the same temperature with a solution of urea containing 6.2 g/L.

Answer 1

`pi = C_"glucose" * R * T = C_"urea" * R * T`    ...(Because R and T are same)

urea = 6.2 g/L

Molar mass of urea = 60 g/mol

`C_"urea" = 6.2/60`

= 0.1033 mol/L

Molar mass of glucose = 180 g/mol

Mass of glucose per litre = 0.1033 × 180

= 18.6 g/L

∴ The concentration of glucose solution that is isotonic with 6.2 g/L urea is 18.6 g/L.