मराठी

Calculate coefficient of variation for the data given below [Given : 3.3 = 1.8166] C.I. 5 – 15 15 – 25 25 – 35 35 – 45 45 – 55 55 – 65 65 – 75 f 6 7 15 25 8 18 21

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प्रश्न

Calculate coefficient of variation for the data given below [Given : `sqrt(3.3)` = 1.8166]

C.I. 5 – 15  15 – 25 25 – 35 35 – 45 45 – 55 55 – 65 65 – 75
f 6 7 15 25 8 18 21
बेरीज
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उत्तर

C.I. Mi value
(xi)
Frequency 
(fi)
fixi fixi2
5 – 15 10 6 60 600
15 – 25 20 7 140 2800
25 – 35 30 15 450 13500
35 – 45 40 25 1000 40000
45 – 55 50 8 400 20000
55 – 65 60 18 1080 64800
65 – 75 70 21 1470 102900
Total   N = 100 `sum"f"_"i""x"_"i"` = 4600 `sum"f"_"i""x"_"i"^2` = 244600

`bar"x" = (sum"f"_"i""x"_"i")/"N" = 4600/100` = 46

Var (X) = `sigma_"x"^2`

= `1/"N" sum"f"_"i""x"_"i"^2 - (bar"x")^2`

= `1/100 xx 244600 - (46)^2` 

= 2446 – 2116
= 330
S.D. = `sigma_"x"^2`
= `sqrt(330)`
= `sqrt(3.3 xx 100)`
= `10sqrt(3.3)`
= 10 × 1.8166
= 18.166
∴ C.V. = `100 xx sigma_"x"/bar"x"`

= `100 xx (18.166)/46`
= 39.49%

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Coefficient of Variation
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 2: Measures of Dispersion - Miscellaneous Exercise 2 [पृष्ठ ३६]

APPEARS IN

बालभारती Mathematics and Statistics (Commerce) Part 2 [English] Standard 11 Maharashtra State Board
पाठ 2 Measures of Dispersion
Miscellaneous Exercise 2 | Q 16 | पृष्ठ ३६

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