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प्रश्न
Answer the following :
Calculate coefficient of variation for the data given below:
| Income (Rs.) |
3000 - 4000 | 4000 - 5000 | 5000 - 6000 | 6000 - 7000 | 7000 - 8000 | 8000 - 9000 | 9000 - 10000 |
| No. of families | 24 | 13 | 15 | 28 | 12 | 8 | 10 |
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उत्तर
We construct the following table to compute C.V. :
| C.I. |
Mid-value xi |
fi |
ui = `(x_"i" - "A")/"h"` A = 6500, h = 1000 |
fiui | fiui2 = fiui × ui |
| 3000 - 4000 | 3500 | 24 | – 3 | – 72 | 216 |
| 4000 - 5000 | 4500 | 13 | – 2 | – 26 | 52 |
| 5000 - 6000 | 5500 | 15 | – 1 | – 15 | 15 |
| 6000 - 7000 | 6500 | 28 | 0 | 0 | 0 |
| 7000 - 8000 | 7500 | 12 | 1 | 12 | 12 |
| 8000 - 9000 | 8500 | 8 | 2 | 16 | 32 |
| 9000 - 10000 | 9500 | 10 | 3 | 30 | 90 |
| `sumf_"i"` = 110 | – | `sumf_"i"u_"i"` = –55 | `sumf_"i"u_"i"^2` = 417 |
From the table,
`sumf_"i"` = 110, `sumf_"i"u_"i"` = −55, `sumf_"i"u_"i"^2` = 417
∴ `bar(u) = (sumf_"i"u_"i")/(sumf_"i") = (-55)/110` = – 0.5
∴ `bar(x) = "A" + "h"bar(u)` = 6500 + 1000(– 0.5) = 6000
`sigma_u^2 = (sumf_"i"u_"i"^2)/(sumf_"i") - (baru)^2`
= `417/110 − (-0.5)^2`
= 3.791 − 0.25
= 3.541
∴ `sigma_u sqrt(3.541)` = 1.882
∴ `sigma_x = "h"sigma_x` = 1000 × 1.882 = 1882
C.V. = `sigma_x/bar(x) xx 100`
= `1882/6000 xx 100`
= 31.36
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