मराठी

Calculate: 3^14/3 × 5^−4/3 × 15^−2/3 - Mathematics

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प्रश्न

Calculate:

`3^(14/3) xx 5^((-4)/3) xx 15^((-2)/3)`

बेरीज
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उत्तर

Given,

`3^(14/3) xx 5^((-4)/3) xx 15^((-2)/3)`

We need to simplify the given terms.

Thus, `3^(14/3) xx 5^((-4)/3) xx 15^((-2)/3)`

⇒ `3^((18/3 + (-4)/3)) xx 5^((-4)/3) xx 15^((-2)/3)`

⇒ `3^(18/3) xx 3^((-4)/3) xx 5^((-4)/3) xx 15^((-2)/3)`

If powers are same and multiplied the base. i.e, an × bn = (a × b)n

⇒ `3^6 xx (15)^((-4)/3) xx (15)^((-2)/3)`

⇒ `3^6 xx (15)^((-4)/3 - 2/3)`  ...[∴ an × am = an + m]

⇒ `3^6 xx (15)^((-6)/3)`

⇒ `3^6 xx (15)^-2`

⇒ `3^6 xx (3 xx 5)^-2`  ...[∴ an × bn = (a × b)n]

⇒ `3^6 xx 3^-2 xx 5^-2`  ...[∴ an × am = an + m]

⇒ `3^4 xx 5^-2`   ...`[∴ a^-n = 1/a^n]`

= `3^4/5^2`

= `81/25`

Hence, the required is `81/25`.

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पाठ 6: Indices - EXERCISE 6 [पृष्ठ ६७]

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बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
पाठ 6 Indices
EXERCISE 6 | Q 8. (iii) | पृष्ठ ६७
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