Question

Calcium carbonate react with dilute hydrochloric acid as given below:

\[\ce{CaCO3 + 2HCl -> CaCl2 + H2O + CO2}\]

How many moles of \[\ce{HCl}\] will react with 5 moles of calcium carbonate?

Answer 1

2 moles of HCl are used for 1 mole of \[\ce{CaCO3}\]

i.e., \[\ce{CaCO3}\]      \[\ce{HCl}\]

\[\ce{1mole -> 2 mole}\]

\[\ce{5 mole -> 5 × 2 = 10 moles}\]

Hence 10 moles of HCl will react with 5 moles of calcium carbonate.