Advertisements
Advertisements
प्रश्न
Basha borrowed ₹ 8,500 from a bank at a particular rate of simple interest. After 3 years, he paid ₹ 11,050 to settle his debt. At what rate of interest he borrowed the money?
Advertisements
उत्तर
Let the rate of interest be r% per annum
Here Principal P = ₹ 8,500
Time n = 3 years
Total amount paid = ₹ 11,050
A = P + 1 = ₹ 11,050
i.e. 8,500 + 1 = ₹ 11,050
I = ₹ 11,050 – ₹ 8,500 = ₹ 2,550
Also we know that I = `"Pnr"/100` = ₹ 2,550
`(8,500 xx 3 xx "r")/100` = ₹ 2,550
r = `(2550 xx 100)/(8500 xx 3)`
r = 10%
Rate of interest r = 10%
APPEARS IN
संबंधित प्रश्न
The simple interest on a certain sum of money is `3/8` of the sum in `6 1/4` years. Find the rate percent charged.
What sum of money borrowed on 24th May will amount to Rs.10210.20 on 17th October of the same year at 5 percent per annum simple interest.
Mahesh deposited rupees 8650 in a bank at a rate of 6 p.c.p.a. How much money will he get at the end of the year in all?
Sheela has paid simple interest on a certain sum for 4 years at 9.5% per annum is ₹ 21,280. Find the sum
Stephen invested ₹ 10,000 in a savings bank account that earned 2% simple interest. Find the interest earned if the amount was kept in the bank for 4 years
The time period after which the interest is added each time to form a new principal is called the ______.
Simple interest on a given amount is always less than or equal to the compound interest on the same amount for the same time period and at the same rate of interest per annum.
Interest on ₹ 12500 at 18% per annum for a period of 2 years and 4 months is ______.
Interest = `(P xx R xx T)/100`, where T is ______ R% is ______ and P is ______.
Chalk contains 10% calcium, 3% carbon and 12% oxygen. Find the amount of carbon and calcium (in grams) in `2 1/2` kg of chalk.
