Advertisements
Advertisements
प्रश्न
The simple interest on a certain sum of money is `3/8` of the sum in `6 1/4` years. Find the rate percent charged.
Advertisements
उत्तर १
Let P = Rs.8
S.I. = Rs.`3/8xx8`
= Rs.3
T =`6 1/4` years = `25/4` years
We know that :
R =`(100xx"I")/("P"xx"T")`
`=(100xx3)/(8xx25/4)=(100xx3)/8xx4/25=2xx3`
= 6%
उत्तर २
Given:
- Simple interest is `3/8` of the sum,
- Time (T) = `6 1/4` = 6.25 years,
- Formula for simple interest:
`SI = (P.R.T)/100`
Step 1: Represent simple interest in terms of the principal
`SI = 3/8.P`
Substitute SI into the formula:
`3/8.P = (P.R.T)/100`
Step 2: Cancel P (since P≠0) and solve for R:
`3/8 = (Rxx6.25)/100`
Rearrange
`R = (3/8 xx100)/6.25`
Step 3: Simplify:
`R = (3xx100)/(8xx6.25)=300/50=6`
= 6
APPEARS IN
संबंधित प्रश्न
The interest on a certain sum of money is 0.24 times itself in 3 years. Find the rate of interest.
At a rate of 10 p.c.p.a., what would be the interest for one year on rupees 6000?
Aravind borrowed a sum of ₹ 8,000 from Akash at 7% per annum. Find the interest and amount to be paid at the end of two years
In how much time will the simple interest on ₹ 3,000 at the rate of 8% per annum be the same as simple interest on ₹ 4,000 at 12% per annum for 4 years?
The time period after which the interest is added each time to form a new principal is called the ______.
The difference of interest for 2 years and 3 years on a sum of ₹ 2100 at 8% per annum is ______.
Interest on ₹ 1200 for `1 1/2` years at the rate of 15% per annum is ₹ 180.
Amount received after depositing ₹ 800 for a period of 3 years at the rate of 12% per annum is ₹ 896.
Radhika borrowed ₹ 12000 from her friends. Out of which ₹ 4000 were borrowed at 18% and the remaining at 15% rate of interest per annum. What is the total interest after 3 years?
Dhruvika invested money for a period from May 2006 to April 2008 at rate of 12% per annum. If interest received by her is ₹ 1620, find the money invested.
