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प्रश्न
At constant temperature, the effect of change of pressure on the volume of a gas was as given below:
|
Pressure in atmosphere |
Volume in liters |
|
0.20 |
112 |
|
0.25 |
89.2 |
|
0.40 |
56.25 |
|
0.60 |
37.40 |
|
0.80 |
28.10 |
|
1.00 |
22.4 |
(a) Plot the following graphs
- P vs V
- P vs 1/V
- PV vs P
Interpret each graph in terms of the law.
(b) Assuming that the pressure values given above are correct, find the correct measurement of the volume.
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उत्तर
|
P/atm |
V/dm3 |
1/V |
PV |
|
0.2 |
112 |
0.009 |
22.4 |
|
0.25 |
89.2 |
0.011 |
22.4 |
|
0.4 |
56.25 |
0.018 |
22.4 |
|
0.6 |
37.4 |
0.027 |
22.4 |
|
0.8 |
28.1 |
0.036 |
22.4 |
|
1 |
22.4 |
0.045 |
22.4 |
(a) Plot the following graphs:
1. P vs. V:

At constant temperature, P is inversely proportional to V. Thus, the plot of V versus P will be a rectangular hyperbola.
2. P vs. 1/V:

According to Boyle's law, at a constant temperature, the pressure of a fixed amount of gas varies inversely to its volume. The graph of pressure versus 1/V shows a positive slope.
3. PV vs. P:

According to Boyle's law, the product of pressure and volume is constant at a constant temperature. The graph of PV versus P is constant which indicates that the given gas obeys Boyle's law.
(b) The correct measurements of the volume are given below:
|
P/atm |
V/dm3 |
|
0.2 |
112 |
|
0.25 |
89.6 |
|
0.4 |
56 |
|
0.6 |
37.33 |
|
0.8 |
28 |
|
1 |
22.4 |
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