मराठी

Assertion (A): The quadratic equation $$x^{2} - 4x + 3 = 0$$ has both real roots. Reason (R): The equation $$ax^{2} + bx + c = 0,\ a\neq 0$$ has both real roots, if $$(b^{2} - 4ac) \geq 0$$.

Advertisements
Advertisements

प्रश्न

Assertion (A): The quadratic equation $$x^{2}-4x+3=0$$ has both real roots.

Reason (R): The equation $$ax^{2}+bx+c=0,\ a\neq 0$$ has both real roots, if $$(b^{2}-4ac)\geq 0$$.

पर्याय

  • Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).

  • Both Assertion (A) and Reason (R) are true but Reason (R) is not a correct explanation of Assertion (A).

  • Assertion (A) is true and Reason (R) is false.

  • Assertion (A) is false and Reason (R) is true.

MCQ
विधान आणि तर्क
Advertisements

उत्तर

Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).

Explanation:

Step 1 – Assertion: A is true. The discriminant is $$(-4)^{2}-4(1)(3)=16-12=4>0,$$ so the equation has two real roots.

Step 2 – Reason: R is true. A non-negative discriminant gives real roots.

Step 3 – Link: The equation’s discriminant is positive, so the condition in R directly establishes A.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 20: Additional Questions - Quadratic Equations [पृष्ठ ९८७]

APPEARS IN

आर. एस. अग्रवाल Mathematics [English] Class 10
पाठ 20 Additional Questions
Quadratic Equations | Q 12. | पृष्ठ ९८७
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×