मराठी

Assertion (A): In the following frequency distribution, Height (in cm) Number of students 110–115 15 115–130 13 130–145 11 145–160 10 160–175 11 the sum of the lower limit of the modal class

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प्रश्न

Assertion (A): In the following frequency distribution,

Height (in cm) Number of
students
110–115 15
115–130 13
130–145 11
145–160 10
160–175 11

the sum of the lower limit of the modal class and the upper limit of the median class is 240.

Reason (R): The median class of the given frequency distribution is 130–145.

पर्याय

  • Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).

  • Both Assertion (A) and Reason (R) are true but Reason (R) is not a correct explanation of Assertion (A).

  • Assertion (A) is true and Reason (R) is false.

  • Assertion (A) is false and Reason (R) is true.

MCQ
विधान आणि तर्क
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उत्तर

Assertion (A) is false and Reason (R) is true.

Explanation:

Step 1 – Assertion: A is false. The modal class is 110–115, whose lower limit is 110. The upper limit of the median class is 145, so their sum is $$110 + 145 = 255$$, not 240.

Step 2 – Reason: R is true. The total frequency is $$N = 60$$, so $$\frac{N}{2} = 30$$. The cumulative frequency just greater than 30 is 39, corresponding to the class 130–145.

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पाठ 20: Additional Questions - Mean, Median, Mode of Grouped Data, Cumulative Frequency Graph and Ogive [पृष्ठ १०६०]

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आर. एस. अग्रवाल Mathematics [English] Class 10
पाठ 20 Additional Questions
Mean, Median, Mode of Grouped Data, Cumulative Frequency Graph and Ogive | Q 9. | पृष्ठ १०६०
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