मराठी

Assertion (A): If the radius of a semicircular protractor is $$7\ \text{cm}$$ then its perimeter is $$36\ \text{cm}$$. Reason (R): The perimeter of a semicircular protractor of radius $$r$$ cm

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प्रश्न

Assertion (A): If the radius of a semicircular protractor is $$7\ \text{cm}$$ then its perimeter is $$36\ \text{cm}$$.

Reason (R): The perimeter of a semicircular protractor of radius $$r$$ cm is $$r(\pi + 2)$$ cm.

पर्याय

  • Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).

  • Both Assertion (A) and Reason (R) are true but Reason (R) is not a correct explanation of Assertion (А).

  • Assertion (A) is true and Reason (R) is false.

  • Assertion (A) is false and Reason (R) is true.

MCQ
विधान आणि तर्क
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उत्तर

Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).

Explanation:

Step 1 – Assertion: A is true. Substituting $$r = 7\ \text{cm}$$ and $$\pi = \frac{22}{7}$$ into the perimeter formula gives $$7\left(\frac{22}{7} + 2\right) = 36\ \text{cm}$$.

Step 2 – Reason: R is true. The perimeter consists of the semicircular arc and its diameter, giving $$\frac{1}{2}(2\pi r) + 2r = r(\pi + 2)$$.

Step 3 – Link: The reason gives the formula used to find the protractor’s perimeter, so it correctly explains the assertion.

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पाठ 20: Additional Questions - Area of Circle, Sector and Segment [पृष्ठ १०३५]

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आर. एस. अग्रवाल Mathematics [English] Class 10
पाठ 20 Additional Questions
Area of Circle, Sector and Segment | Q 3. | पृष्ठ १०३५
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