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प्रश्न
Arrange the following compounds on the basis of lattice energies in decreasing (descending) order:
BeF2, AlCl3, LiCl, CaCl2, NaCl
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उत्तर
AlCl3 > BeF2 > CaCl2 > LiCl > NaCl
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संबंधित प्रश्न
Select and write the most appropriate alternatives from the given choices.
Which of the following is true for CO2?
Select and write the most appropriate alternatives from the given choices.
Which O2 molecule is paramagnetic. It is explained on the basis of ______.
Draw an orbital diagram of Hydrogen fluoride molecule
BF3 molecule is planar but NH3 pyramidal. Explain.
What are the interacting forces present during the formation of a molecule of a compound?
Why is O2 molecule paramagnetic?
Assertion: Oxygen molecule is paramagnetic.
Reason: It has two unpaired electron in its bonding molecular orbital.
Of the following molecules, which have shape similar to carbon dioxide?
Draw MO diagram of CO and calculate its bond order.
Discuss the formation of N2 molecule using MO Theory.
4p, 4d, 5s and 5p orbitals are arranged in the order of decreasing energy. The CORRECT option is:
Which of the following statements is INCORRECT?
Which one of the following sets CORRECTLY represents the increase in the paramagnetic property of the ions?
What is the bond order of B2 molecule?
According to MOT, the number of unpaired electrons in O2 molecule is ____________.
Identify the CORRECT option according to MOT.
According to molecular orbital theory, antibonding molecular orbitals of O2 contain ____________.
According to molecular orbital theory, which of the following will NOT be viable?
H2 molecule is more stable than Li2 molecule, because ______.
Which of the following molecules has bond order zero?
The electronic configuration of Be2 molecule according MOT is ______.
Bonding in which of the following diatomic molecule(s) become(s) stronger, on the basis of MO Theory, by removal of an electron?
(A) NO
(B) N2
(C) O2
(D) C2
(E) B2
Choose the most appropriate answer from the options given below:
The correct statement with regard to \[\ce{H^+_2}\] and \[\ce{H^-_2}\] is:
