Advertisements
Advertisements
प्रश्न
Area of the region bounded by the curve y = cosx between x = 0 and x = π is ______.
पर्याय
2 sq.units
4 sq.units
3 sq.units
1 sq.units
Advertisements
उत्तर
Area of the region bounded by the curve y = cosx between x = 0 and x = π is 2 sq.units.
Explanation:

Given that: y = cos x, x = 0, x = π
Required area = `int_0^(pi/2) cos x "d"x + |int_(pi/2)^pi cos x "d"x|`
= `[sin x]_0^(pi/2) + |(sin x)_(pi/2)^pi|`
= `[sin pi/2 - sin 0] + |[sin pi - sin pi/2]|`
= `(1 - 0) + |0 - 1|`
= 1 + 1
= 2 sq.units
APPEARS IN
संबंधित प्रश्न
Find the area of the region bounded by the parabola y2 = 16x and the line x = 3.
Find the area of the sector of a circle bounded by the circle x2 + y2 = 16 and the line y = x in the ftrst quadrant.
Using integration, find the area of the region bounded by the line 2y = 5x + 7, x-axis and the lines x = 2 and x = 8.
Using definite integrals, find the area of the circle x2 + y2 = a2.
Sketch the graph y = |x + 1|. Evaluate\[\int\limits_{- 4}^2 \left| x + 1 \right| dx\]. What does the value of this integral represent on the graph?
Find the area of the region bounded by x2 + 16y = 0 and its latusrectum.
Find the area of the region common to the parabolas 4y2 = 9x and 3x2 = 16y.
Using integration, find the area of the region bounded by the triangle ABC whose vertices A, B, C are (−1, 1), (0, 5) and (3, 2) respectively.
Find the area of the region bounded by \[y = \sqrt{x}, x = 2y + 3\] in the first quadrant and x-axis.
Find the area of the region bounded by \[y = \sqrt{x}\] and y = x.
Find the area of the region in the first quadrant enclosed by x-axis, the line y = \[\sqrt{3}x\] and the circle x2 + y2 = 16.
Using integration, find the area of the triangle ABC coordinates of whose vertices are A (4, 1), B (6, 6) and C (8, 4).
Find the area of the region {(x, y): x2 + y2 ≤ 4, x + y ≥ 2}.
Using integration, find the area of the following region: \[\left\{ \left( x, y \right) : \frac{x^2}{9} + \frac{y^2}{4} \leq 1 \leq \frac{x}{3} + \frac{y}{2} \right\}\]
Find the area enclosed by the curves 3x2 + 5y = 32 and y = | x − 2 |.
If the area above the x-axis, bounded by the curves y = 2kx and x = 0, and x = 2 is \[\frac{3}{\log_e 2}\], then the value of k is __________ .
The area of the region bounded by the parabola y = x2 + 1 and the straight line x + y = 3 is given by
The area bounded by the y-axis, y = cos x and y = sin x when 0 ≤ x ≤ \[\frac{\pi}{2}\] is _________ .
Area of the region bounded by the curve y2 = 4x, y-axis and the line y = 3, is
Find the coordinates of a point of the parabola y = x2 + 7x + 2 which is closest to the straight line y = 3x − 3.
Using integration, find the area of the smaller region bounded by the ellipse `"x"^2/9+"y"^2/4=1`and the line `"x"/3+"y"/2=1.`
Find the area of the region bounded by the parabolas y2 = 6x and x2 = 6y.
Find the area of region bounded by the line x = 2 and the parabola y2 = 8x
Using integration, find the area of the region bounded by the line 2y = 5x + 7, x- axis and the lines x = 2 and x = 8.
Find the area bounded by the lines y = 4x + 5, y = 5 – x and 4y = x + 5.
Draw a rough sketch of the given curve y = 1 + |x +1|, x = –3, x = 3, y = 0 and find the area of the region bounded by them, using integration.
The area of the region bounded by the y-axis, y = cosx and y = sinx, 0 ≤ x ≤ `pi/2` is ______.
The area of the region bounded by the curve x2 = 4y and the straight line x = 4y – 2 is ______.
The area of the region bounded by the curve y = `sqrt(16 - x^2)` and x-axis is ______.
The area of the region bounded by the curve y = x + 1 and the lines x = 2 and x = 3 is ______.
Area lying in the first quadrant and bounded by the circle `x^2 + y^2 = 4` and the lines `x + 0` and `x = 2`.
Find the area of the region bounded by the curve `y^2 - x` and the line `x` = 1, `x` = 4 and the `x`-axis.
What is the area of the region bounded by the curve `y^2 = 4x` and the line `x` = 3.
The area enclosed by y2 = 8x and y = `sqrt(2x)` that lies outside the triangle formed by y = `sqrt(2x)`, x = 1, y = `2sqrt(2)`, is equal to ______.
For real number a, b (a > b > 0),
let Area `{(x, y): x^2 + y^2 ≤ a^2 and x^2/a^2 + y^2/b^2 ≥ 1}` = 30π
Area `{(x, y): x^2 + y^2 ≥ b^2 and x^2/a^2 + y^2/b^2 ≤ 1}` = 18π.
Then the value of (a – b)2 is equal to ______.
The area of the region S = {(x, y): 3x2 ≤ 4y ≤ 6x + 24} is ______.
