Question

Answer the following question:

Find the distance of the origin from the line 12x + 5y + 78 = 0

Answer 1

Let p be the perpendicular distance of origin from the line 12x + 5y + 78 = 0.

Here, a = 12, b = 5, c = 78

∴ p = `|"c"/sqrt("a"^2 + "b"^2)|`

∴ p = `|78/sqrt(12^2 + 5^2)|`

= `|78/sqrt(144 + 25)|`

= `78/13`

= 6 units