Question

Answer the following question:

Find the distance between the parallel lines 3x + 4y + 3 = 0 and 3x + 4y + 15 = 0

Answer 1

Equations of the given parallel lines are

3x + 4y + 3 = 0 and 3x + 4y + 15 = 0

Here, a = 3, b = 4, c₁ = 3 and c₂ = 15

∴ Distance between the parallel lines

= `|("c"_1 - "c"_2)/sqrt("a"^2 + "b"^2)|`

= `|(3 - 15)/sqrt(3^2 + 4^2)|`

= `|(-12)/sqrt(9 + 16)|`

= `12/5"units"`