Question

An organic compound ‘A’, molecular formula C₂H₆O oxidises with CrO₃ to form a compound ‘B’. Compound ‘B’ on warming with iodine and aqueous solution of NaOH gives a yellow precipitate of compound ‘C’. When compound ‘A’ is heated with conc. H₂SO₄ at 413 K gives a compound ‘D’, which, on reaction with excess HI gives compound ‘E’. Identify compounds ‘A’, ‘B’, ‘C’, ‘D’ and ‘E’, and write the chemical equations involved.

Answer 1

\[\ce{\underset{(A)}{\underset{Ethanol}{C2H5OH}} + CrO3 -> CH3CHO}\]

\[\ce{\underset{(B)}{\underset{Acetaldehyde}{CH3CHO}} + 3I2 + 4NaOH ->\underset{(C)}{\underset{Iodoform}{CHI3 (yellow precipitate)}} + HCOONa + 2H2O + 3NaI}\]

\[\ce{C2H5OH  + (conc{.} H2SO4, 413 K) ->\underset{(D)}{\underset{Diethylether}{C2H5OC2H5}} + H2O}\]

\[\ce{C2H5OC2H5 + HI -> \underset{(E)}{\underset{Ethyl iodide}{2C2H5I}} + H2O}\]