मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान इयत्ता ११

An Ordinary Electric Fan Does Not Cool the Air, Still It Gives Comfort in Summer. Explain

Advertisements
Advertisements

प्रश्न

An ordinary electric fan does not cool the air, still it gives comfort in summer. Explain

टीपा लिहा
Advertisements

उत्तर

An ordinary electric fan does not cool the air, still it gives comfort in summer because it circulates the air present in the room. Due to this, evaporation takes place and we feel cooler.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 28: Heat Transfer - Short Answers [पृष्ठ ९७]

APPEARS IN

एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
पाठ 28 Heat Transfer
Short Answers | Q 7 | पृष्ठ ९७

संबंधित प्रश्‍न

On a cold winter night you are asked to sit on a chair. Would you like to choose a metal chair or a wooden chair? Both are kept in the same lawn and are at the same temperature.


The temperature of the atmosphere at a high altitude is around 500°C. Yet an animal there would freeze to death and not boil. Explain.


Newton's law of cooling is a special case of


A body cools down from 65°C to 60°C in minutes. It will cool down from 60°C to 55°C in


Answer the following question.

State Newton’s law of cooling and explain how it can be experimentally verified.


Solve the following problem.

A metal sphere cools at the rate of 0.05 ºC/s when its temperature is 70 ºC and at the rate of 0.025 ºC/s when its temperature is 50 ºC. Determine the temperature of the surroundings and find the rate of cooling when the temperature of the metal sphere is 40 ºC.


A bucket full of hot water cools from 85 °C to 80 °C in time T1, from 80 °C to 75 °C in time T2 and from 75 °C to 70 °C in time T3, then ______.


Newton's law of cooling leads to the expression: 


A tub of hot water cools from 80°C to 75°C in time t1 from 75°C to 70°C in time t2, and from 70°C to 65°C in time t3 then:


One day in the morning, Ramesh filled up 1/3 bucket of hot water from geyser, to take bath. Remaining 2/3 was to be filled by cold water (at room temperature) to bring mixture to a comfortable temperature. Suddenly Ramesh had to attend to something which would take some times, say 5-10 minutes before he could take bath. Now he had two options: (i) fill the remaining bucket completely by cold water and then attend to the work, (ii) first attend to the work and fill the remaining bucket just before taking bath. Which option do you think would have kept water warmer? Explain.


In 5 minutes, a body cools from 75°C to 65°C at a room temperature of 25°C. The temperature of the body at the end of the next 5 minutes is ______°C.


What is the shape of the cooling curve T vs t?


If we plot \[\frac{dT}{dt}\] vs (T−T₀), what graph do we get?


Why must the surrounding temperature T₀ remain constant in the experiment?


A metal sphere cools in a room at 30°C. At T = 70°C, dT/dt = −1.6°C/min. Find C.


A body cools from 60°C to 40°C in 6 minutes. After next 6 minutes its temperature will be (Temperature of the surroundings is 10°C) ______.


A body cools from temperature \[(3\theta)^{\circ}C\] to \[(2\theta)^{\circ}C\] in 10 minute. Then it cools from \[(2\theta)^{\circ}C\] to \[(\theta_1)^{\circ}C\] in next 10 minutes. The room temperature is \[(\theta)^{\circ}C.\] Assuming that the newton's law of cooling is applicable the value of \[(\theta_1)^{\circ}C\] is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×