Advertisements
Advertisements
प्रश्न
An object undergoes an acceleration of 8 ms-2 starting from rest. Find the distance travelled in 5 seconds.
Advertisements
उत्तर
Initial velocity of the object = 0 ms-1
Acceleration of the object = 8 ms-2.
Time = 5 s.
Distance covered would be S = ut + 1/2 at2.
S = 1/2 X 8 X 5 X5 = 100 m.
APPEARS IN
संबंधित प्रश्न
A light ball falling on ground, after striking the ground rises upwards. Explain the reason.
What is the importance of law of gravitation ?
The gravitational force between two bodies is :
The force of attraction between two bodies at certain separation is 10 N. What will be the force of attraction between them if the separation is reduced to half?
State unit of mass in CGS system.
Why are passengers thrown in the forward direction when a running bus stops suddenly?
Why do passengers tend to fall backward when it starts suddenly?
Define the constant of gravitation.
he gravity is a particular case of _________.
A boy pushes a wall with a force of 30 N towards east. What force is exerted by the wall on the boy?
