Advertisements
Advertisements
प्रश्न
An object undergoes an acceleration of 8 ms-2 starting from rest. Find the distance travelled in 5 seconds.
Advertisements
उत्तर
Initial velocity of the object = 0 ms-1
Acceleration of the object = 8 ms-2.
Time = 5 s.
Distance covered would be S = ut + 1/2 at2.
S = 1/2 X 8 X 5 X5 = 100 m.
APPEARS IN
संबंधित प्रश्न
Name the S.I. and C.G.S. units of force. How are they related?
Why does a glass vessel break when it falls on a hard floor, but it does not break when it falls on a carpet?
State unit of momentum in the CGS system.
Explain the following:
Why does a boatman push the bank backward with a long bamboo pole, on launching his boat in the water?
If a number of forces act on a stationary body at the same point, then what do you conclude from it?
Why are passengers thrown in the forward direction when a running bus stops suddenly?
Can internal forces change the velocity of a body?
Define the constant of gravitation.
Name and state the action and reaction in the following case:
Firing a bullet from a gun.
A force acts for 0.1 s on a body of mass 3.2 kg initially at rest. The force then ceases to act and the body moves through 3 m in the next one second. Calculate the magnitude of force.
