Question

An experiment was set up with the circuit diagram shown in figure.

Given that R₁ = 10 Ω, R₂ = R₃ = 5 Ω, r = 0 Ω and E = 5 V.

The potential difference across R₃ is ______.

पर्याय

• 1.5 V

• 2 V

• 2.5 V

• 3 V

Answer 1

The potential difference across R₃ is 2.5 V.

Explanation:

Current through cf arm = E/(R₂ + R₃)

= 5/10

= 0.5 A

So, the potential difference across R₃ is IR₃

= 0.5 × 5

= 2.5 V