Advertisements
Advertisements
प्रश्न
An electron, an alpha particle and a proton have the same kinetic energy.
Which one of these particles has the largest de-Broglie wavelength?
Advertisements
उत्तर
De-Broglie’s wavelength is given as, λ = `h/(sqrt(2mK))`
Where, h is Planck’s constant, m is the mass of the particle, K is the kinetic energy of the particle
The mass of the electron is least among an electron, an alpha particle, and a photon.
`because lambda ∝ 1/sqrtm`, therefore, the electron has the largest de-Broglie wavelength.
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
