Question

An electromagnetic wave going through vacuum is described by
E = E₀ sin (kx − ωt); B = B₀ sin (kx − ωt).
Which of the following equations is true?

पर्याय

• E₀ k = B₀ ω

• E₀ B₀ = ωk

• E₀ ω = B₀ k

• None of these

Answer 1

E₀ k = B₀ ω

Explanation:

The relation between E₀  and B₀ is given by `"E"_0/"B"_0 = "C"` ...(1)

Here, c = speed of the electromagnetic wave

The relation between ​ω (the angular frequency) and k (wave number):

`ω/"k" = "c"` ...(2)

Therefore, from (1) and (2), we get :

`"E"_0/"B"_0 = ω/"k" = "c"`

⇒ `"E"_0"k" = "B"_0ω`