Question

An effort of 10 kgf is applied on a machine through a displacement of 105 cm when a load of 200 kgf moves through a distance of 5 cm. Calculate (i) mechanical advantage, (ii) velocity ratio and (iii) efficiency of the machine.

Answer 1

Given Data:

Effort (E) = 10 kgf

Displacement of effort (d_E) = 105 cm

Load (L) = 200 kgf

Displacement of load (d_L) = 5 cm

(i) Mechanical Advantage (MA) = `"Load (L)"/"Effort (E)"`

= `200/10`

= 20

(ii) Velocity Ratio (VR) = `("Displacement of Effort" (d_E))/("Displacement of Load" (d_L))`

= `105/5`

= 21

(iii) Efficiency (η) = `(MA)/(VR) xx 100%`

= `20/21 xx 100%`

= 95.24%