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प्रश्न
An almond nut can be broken by applying a force of 2 kgf on the extreme end of the handle of a nutcracker which is 25 cm long. If the nut is placed at a distance of 5 cm from its hinge, calculate the maximum resistance offered by the nut.
संख्यात्मक
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उत्तर
Nutcracker is a lever of second order.
Given: Load arm (d) = 5 cm
∴ Effort arm (D) = 25 cm
Effort (E) = 2 kgf, Load (L) = ?
Now, Load × load arm = Effort × effort arm
Load × 5 cm = 2 kgf × 25 cm
\[ \therefore\ \text{Load} = \frac{2\ \mathrm{kgf} \times 25\ \mathrm{cm}}{5\ \mathrm{cm}} \]
= 10 kgf
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