Advertisements
Advertisements
प्रश्न
A crowbar of length 2.5 m is pivoted at a point 25 cm from its tip. Calculate (a) mechanical advantage of crowbar (b) the maximum load displaced by it by applying an effort of 100 kgf on its extreme end.
संख्यात्मक
Advertisements
उत्तर
The crowbar is a lever of the 1st order.
Given: Total length of crowbar = 2.5 m = 250 cm
Load arm = 25 cm
∴ Effort arm = (250 − 25) cm = 225 cm
\[ \text{(a) Mech. advantage} = \text{velocity ratio} = \frac{\text{effort arm}}{\text{load arm}}\]
\[= \frac{225\ \mathrm{cm}}{25\ \mathrm{cm}}\]
= 9
(b) Taking moments about the pivot:
Load × load arm = Effort × effort arm
L × 25 cm = 100 kgf × 225 cm
\[ \therefore\ \mathrm{L} = \frac{100\ \mathrm{kgf} \times 225\ \mathrm{cm}}{25\ \mathrm{cm}}\]
= 900 kgf
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
