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प्रश्न
Aldehydes and ketones react with hydroxylamine to form ______.
पर्याय
hydrazones
semicarbazones
cyanohydrins
oxime
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उत्तर
Aldehydes and ketones react with hydroxylamine to form oxime.
Explanation:
When aldehydes and ketones react with hydroxylamine, they undergo nucleophilic addition and create oximes.
APPEARS IN
संबंधित प्रश्न
Arrange the following compound in increasing order of its reactivity in nucleophilic addition reactions.
Benzaldehyde, p-Tolualdehyde, p-Nitrobenzaldehyde, Acetophenone.
Hint: Consider steric effect and electronic effect.
Predict the product of the following reaction:
\[\begin{array}{cc}
\phantom{..............}\ce{O}\\
\phantom{..............}||\\
\ce{R - CH = CH - CHO + NH2 - C - NH - NH2 ->[H+]}\end{array}\]
What is meant by the following term? Give an example of the reaction in the following case.
Oxime
Predict the products formed when cyclohexanecarbaldehyde reacts with the following reagents.
PhMgBr and then H3O+
How are the following compounds prepared?
acetophenone from benzene
How are the following compounds prepared?
benzaldehyde from benzoyl chloride
Write the name of product formed, when acetone is treated with 2, 4-dinitrophenyl hydrazine.
The following questions are case-based questions. Read the passage carefully and answer the questions that follow:
| The carbon-oxygen double bond is polarised in aldehydes and ketones due to higher electronegativity of oxygen relative to carbon. Therefore, they undergo nucleophilic addition reactions with a number of nucleophiles such as HCN, NaHSO3, alcohols, ammonia derivatives and Grignard reagents. Aldehydes are easily oxidised by mild oxidising agents as compared to ketones. The carbonyl group of carboxylic acid does not give reactions of aldehydes and ketones. Carboxylic acids are considerably more acidic than alcohols and most of simple phenols. |
Answer the following:
(a) Write the name of the product when an aldehyde reacts with excess alcohol in the presence of dry HCl. (1)
(b) Why carboxylic acid is a stronger acid than phenol? (1)
(c) (i) Arrange the following compounds in increasing order of their reactivity towards CH3MgBr: (1)
CH3CHO, \[\begin{array}{cc}
\ce{(CH3)3C-C-CH3}\\
\phantom{....}||\\
\phantom{....}\ce{O}
\end{array}\], \[\begin{array}{cc}
\ce{CH3-C-CH3}\\
||\\
\ce{O}
\end{array}\]
(ii) Write a chemical test to distinguish between propanal and propanone. (1)
OR
(c) Write the main product in the following: (2)
| (i) |  |
| (ii) |  |
Draw the structure of the following derivative.
Acetaldehydedimethylacetal
Draw structure of the following derivative:
Acetaldehydedimethylacetal
