Question

Accept a list containing integers randomly. Accept any number and display the position at which the number is found is the list.

Answer 1

Since the list is random (unsorted), use linear search. The program displays the first position using 1-based position numbering.

def linear_search(data_list, number):
    for index, value in enumerate(data_list):
        if value == number:
            return index + 1  # Position for the user
    return -1


numbers = list(map(int, input("Enter list elements: ").split()))
search_number = int(input("Enter number to search: "))
position = linear_search(numbers, search_number)

if position == -1:
    print("Element not found")
else:
    print("Element found at position", position)

Enter list elements: 15 8 24 6 19
Enter number to search: 24
Element found at position 3