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A Wire, Carrying a Current I, is Kept in the X−Y Plane Along the Curve Y = a Sin ( 2 X λ X ) . Magnetic Field

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प्रश्न

A wire, carrying a current i, is kept in the xy plane along the curve y = A sin `((2x)/lamda x)`. magnetic field B exists in the z direction. Find the magnitude of the magnetic force on the portion of the wire between x = 0 and x = λ.

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उत्तर

Given:
Electric current flowing through the wire = i
The wire is kept in the xy plane along the curve, `y = A sin ((2x)/lamda x)` 
Magnetic field (B) exists in the z direction.

We have to find the magnetic force on the portion of the wire between x = 0 and x = λ.
Magnetic force is given by
`vecF = i veclxxvecB`
For a small element dl,
`dvecF = i (dl xx vecB)`
The effective force on the whole wire is equivalent to the force on a starlight wire of length λ placed along the x axis.
So,
F = iB \[\int\limits_0^{λ}\] dl
`⇒ F = ilamdaB`

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Force on a Moving Charge in Uniform Magnetic and Electric Fields
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पाठ 34: Magnetic Field - Exercises [पृष्ठ २३१]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
पाठ 34 Magnetic Field
Exercises | Q 18 | पृष्ठ २३१
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