मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान इयत्ता ११

A Wave is Described by the Equation Y = ( 1 ⋅ 0 M M ) Sin π ( X 2 ⋅ 0 C M − T 0 ⋅ 01 S ) . (A) Find the Time Period and the Wavelength? (B) Write the Equation for the Velocity of the Particles.

Advertisements
Advertisements

प्रश्न

A wave is described by the equation \[y = \left( 1 \cdot 0  mm \right)  \sin  \pi\left( \frac{x}{2 \cdot 0  cm} - \frac{t}{0 \cdot 01  s} \right) .\] 
(a) Find the time period and the wavelength? (b) Write the equation for the velocity of the particles. Find the speed of the particle at x = 1⋅0 cm at time t = 0⋅01 s. (c) What are the speeds of the particles at x = 3⋅0 cm, 5⋅0 cm and 7⋅0 cm at t = 0⋅01 s?
(d) What are the speeds of the particles at x = 1⋅0 cm at t = 0⋅011, 0⋅012, and 0⋅013 s?

बेरीज
Advertisements

उत्तर

The wave equation is represented by \[y = \left( 1 \cdot 0  mm \right)  \sin  \pi\left( \frac{x}{2 \cdot 0  cm} - \frac{t}{0 \cdot 01  s} \right)\]
Let:
Time period = T
Wavelength = λ

\[\left( a \right)  T = 2 \times 0 . 01 = 0 . 02  s = 20  ms\] 

\[ \lambda = 2 \times 2 = 4  cm\]
(b) Equation for the velocity of the particle:

\[=  - 0 . 50  \cos  2\pi\left\{ \left( \frac{x}{4} \right) - \left( \frac{t}{0 . 02} \right) \right\} \times \frac{1}{0 . 02}\] 

\[ \Rightarrow \nu =  - 0 . 50  \cos  2\pi  \left\{ \left( \frac{x}{4} \right) - \left( \frac{t}{0 . 02} \right) \right\}\] 

\[At  x = 1  \text{ and }  t = 0 . 01  s,   \nu =  - 0 . 50  \cos  2\pi  \left\{ \frac{1}{4} - \frac{1}{2} \right\} = 0 .\]

(c) (i) Speed of the particle:
\[At  x = 3  cm  \text{ and }  t = 0 . 01  s,\] 
\[\nu =  - 0 . 50\cos2\pi\left\{ \frac{3}{4} - \frac{1}{2} \right\} = 0\] 
(ii) \[\text{ At } x = 5  cm  \text{ and }  t = 0 . 01  s,\] 

\[\nu = 0  \] 

\[\left( iii \right)  At    x = 7  cm  \text{ and } t = 0 . 1  s,   \nu = 0 . \] 

\[\] 

\[\left( iv \right)  At  x = 1  cm  \text{ and }  t = 0 . 011  s, \] 

\[\nu = 50  \cos  2\pi\left\{ \left( \frac{1}{4} \right) - \left( \frac{0 . 011}{0 . 02} \right) \right\}\] 

\[     =  - 50  \cos  \left( \frac{3\pi}{5} \right) =  - 9 . 7  cm/s\]
(By changing the value of t, the other two can be calculated.)

shaalaa.com
Speed of Wave Motion
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 15: Wave Motion and Waves on a String - Exercise [पृष्ठ ३२४]

APPEARS IN

एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
पाठ 15 Wave Motion and Waves on a String
Exercise | Q 10 | पृष्ठ ३२४

संबंधित प्रश्‍न

Two waves represented by \[y = a\sin\left( \omega t - kx \right)\] and \[y = a\cos\left( \omega t - kx \right)\] \[y = a\cos\left( \omega t - kx \right)\] are superposed. The resultant wave will have an amplitude 


In a stationary wave,
(a) all the particles of the medium vibrate in phase
(b) all the antinodes vibrates in phase
(c) the alternate antinodes vibrate in phase
(d) all the particles between consecutive nodes vibrate in phase.


Calculate the speed of sound in oxygen from the following data. The mass of 22.4 litre of oxygen at STP (T = 273 K and p = 1.0 × 105 N m−2) is 32 g, the molar heat capacity of oxygen at constant volume is Cv = 2.5 R and that at constant pressure is Cp = 3.5 R.


A one-metre long stretched string having a mass of 40 g is attached to a tuning fork. The fork vibrates at 128 Hz in a direction perpendicular to the string. What should be the tension in the string if it is to vibrate in four loops?


In Quincke's experiment, the sound intensity has a minimum value l at a particular position. As the sliding  tube is pulled out by a distance of 16.5 mm, the intensity increases to a maximum of 9 l. Take the speed of sound in air to be 330 m s−1. (a) Find the frequency of the sound source. (b) Find the ratio of the amplitudes of the two waves arriving at the detector assuming that it does not change much between the positions of minimum intensity and maximum intensity.


Find the fundamental, first overtone and second overtone frequencies of an open organ pipe of length 20 cm. Speed of sound in air is 340 ms−1.


A closed organ pipe can vibrate at a minimum frequency of 500 Hz. Find the length of the tube. Speed of sound in air = 340 m s−1.


In a resonance column experiment, a tuning fork of frequency 400 Hz is used. The first resonance is observed when the air column has a length of 20.0 cm and the second resonance is observed when the air column has a length of 62.0 cm. (a) Find the speed of sound in air. (b) How much distance above the open end does the pressure node form?


A copper rod of length 1.0 m is clamped at its middle point. Find the frequencies between 20 Hz and 20,000 Hz at which standing longitudinal waves can be set up in the rod. The speed of sound in copper is 3.8 km s−1.


An open organ pipe has a length of 5 cm. (a) Find the fundamental frequency of vibration of this pipe. (b) What is the highest harmonic of such a tube that is in the audible range? Speed of sound in air is 340 m s−1 and the audible range is 20-20,000 Hz.


An electronically driven loudspeaker is placed near the open end of a resonance column apparatus. The length of air column in the tube is 80 cm. The frequency of the loudspeaker can be varied between 20 Hz and 2 kHz. Find the frequencies at which the column will resonate. Speed of sound in air = 320 m s−1.


A Kundt's tube apparatus has a steel rod of length 1.0 m clamped at the centre. It is vibrated in its fundamental mode at a frequency of 2600 Hz. The lycopodium powder dispersed in the tube collects into heaps separated by 6.5 cm. Calculate the speed of sound in steel and in air.


Calculate the frequency of beats produced in air when two sources of sound are activated, one emitting a wavelength of 32 cm and the other of 32.2 cm. The speed of sound in air is 350 m s−1.


A tuning fork of unknown frequency makes 5 beats per second with another tuning fork which can cause a closed organ pipe of length 40 cm to vibrate in its fundamental mode. The beat frequency decreases when the first tuning fork is slightly loaded with wax. Find its original frequency. The speed of sound in air is 320 m s−1.


Figure shows a person standing somewhere in between two identical tuning forks. each vibrating at 512 Hz. If both the tuning forks move towards right a speed of 5.5 m s−1, find the number of beats heard by the listener. Speed of sound in air = 330 m s−1.


A car moving at 108 km h−1 finds another car in front it going in the same direction at 72 km h−1. The first car sounds a horn that has a dominant frequency of 800 Hz. What will be the apparent frequency heard by the driver in the front car? Speed of sound in air = 330 m s−1.


An operator sitting in his base camp sends a sound signal of frequency 400 Hz. The signal is reflected back from a car moving towards him. The frequency of the reflected sound is found to be 410 Hz. Find the speed of the car. Speed of sound in air = 324 m s−1


A source emitting sound at frequency 4000 Hz, is moving along the Y-axis with a speed of 22 m s−1. A listener is situated on the ground at the position (660 m, 0). Find the frequency of the sound received by the listener at the instant the source crosses the origin. Speed of sound in air = 330 m s−1.


Two tuning forks having frequencies 320 Hz and 340 Hz are sounded together to produce sound waves. The velocity of sound in air is 340 m/s. Find the difference in wavelength of these waves. 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×