Advertisements
Advertisements
प्रश्न
A vessel contains water up to a height of 1.5 m. Taking the density of water 103 kg m-3, acceleration due to gravity 9.8 m s-2 and area of base of vessel 100 cm2, calculate: (a) the pressure and (b) the thrust at the base of vessel.
Advertisements
उत्तर
Given height , h = 1.5 m
Density of water , ρ = 103 kgm-3
Acceleration due to gravity , g = 9.8 m/s2
Area of base of the vessel , a = 100 cm2 = `100 xx 10^-4 "m"^2`
(a) Pressure , P = hρg
or , P = `1.5 xx 10^3 xx 9.8`
or , P = `1.47 xx 10^4 "Nm"^-2`
(b) Thrust = Pressure × area
or , thrust = `1.47 × 10^4 × 100 × 10^-4` N
or , thrust = 147 N
APPEARS IN
संबंधित प्रश्न
What is the scientific name of the 'upward force' acting on an object immersed in a liquid?
What is the unit of relative density?
What is meant by the term buoyancy?
What is the cause of upthrust? At which point can it be considered to act?
A piece of wood if left under water comes to the surface. Explain the reason.
A block of wood is floating on water with its dimensions 50 cm x 50 cm x 50 cm inside water. Calculate the buoyant force acting on the block. Take g = 9.8 N kg-1.
How is thrust different from pressure?
The point at which the force of buoyancy is supposed to act is known as ______.
In a fluid, buoyant force exists because the pressure at the ______ of an object is greater than the pressure at the top.
If the buoyant force is less, the object will float.
