Question

A uniform wire of resistance 50 Ω is cut into 5 equal parts. These parts are now connected in parallel. The equivalent resistance of the combination is ______________ .

पर्याय

• 2 Ω

• 10 Ω

• 250 Ω

• 6250 Ω

Answer 1

2 Ω

 

Resistance of a wire is directly proportional to its length.
So, when we cut the wire into 5 equal parts, the resistance of each part will be 10 Ω.

On connecting these wires in parallel, the net resistance will be

\[\frac{1}{R} = \frac{1}{10} + \frac{1}{10} + \frac{1}{10} + \frac{1}{10} + \frac{1}{10} \]

\[ \Rightarrow R = 2 \Omega\]