Advertisements
Advertisements
प्रश्न
A transformer lowers e.m.f. 220 V to 12 volts. If the number of turns in primary are 8800, how many turns are in secondary coil?
Advertisements
उत्तर
Using `"E"_"p"/"E"_"s" = "N"_"p"/"N"_"s"`
∴ `"200 V"/"12 V" = 8800/"N"_"s"`
∴ `"N"_"s" = (8800 xx 12)/220 = 40 xx 12 = 480`
∴ Number of turns in secondary coil = 480.
संबंधित प्रश्न
State the principle of the step-down transformer and its working.
Find the ratio of primary and secondary currents in terms of turn ratio in an ideal transformer.
Which coil of a step up transformer is made thicker and why?
On which type of current do transformers work?
How are the e.m.f in the primary and secondary coils of a transformer related with the number of turns in these coils?
Name two kind of energy loss in a transformer. How is it minimized?
The primary coil of a transformed has 800 urns and the secondary coil has 8 turns. It is connected to a 220 V a.c. supply. What will be the output voltage?
What is the function of a step-up transformer?
The 300 turn primary of a transformer has resistance 0.82 Ω and the resistance of its secondary of 1200 turns is 6.2 Ω. Find the voltage across the primary if the power output from the secondary at 1600V is 32 kW. Calculate the power losses in both coils when the transformer efficiency is 80%
What type of transformer is used in a mobile phone charger?
