Advertisements
Advertisements
प्रश्न
A train starting from rest moves with a uniform acceleration of 0.2 m/s2 for 5 minutes. Calculate the speed acquired and the distance travelled in this time.
Advertisements
उत्तर
We have to find the distance travelled as well as final velocity of the train. We have the following information given,
Initial velocity, (u) = 0 m/s
Acceleration for the entire journey, (a) = 0.2 m/s2
Time taken,
(t) = (5) (60) s
= 300 s
So, we can find the final velocity using the relation,
v = u + at
Therefore, final velocity of the train is,
v = 0 + (0.2)(300)
= 60 m/s
We can calculate the distance travelled by the train, using the 2nd equation of motion,
`s = ut + 1/2at^2`
Put the values in above equation to find the distance travelled,
`(s) = 0(300) + 1/2(0.2)(300)^2`
= (9000) m
= 9 km
APPEARS IN
संबंधित प्रश्न
What is the Differnece between speed and velocity ?
What does the path of an object look like when it is in uniform motion?
Under which condition is the magnitude of average velocity equal to average speed ?
Arrange the following speed in increasing order (keeping the least speed first):
An athlete running with a speed of 10 m/s.
A car is moving along a straight road at a steady speed. It travels 150 m in 5 seconds:
What is its average speed ?
Write the formula to calculate the speed of a body moving along a circular path. Give the meaning of each symbol which occurs in it.
Express 15 m s-1 in km h-1.
Draw a diagram to show the motion of a body whose speed remains constant, but velocity changes continuously.
A speeding car changes its velocity from 108 kmh−1 to 36 kmh−1 in 4 s. Calculate its deceleration in
- ms−2
- kmh−2.
Which of the following figures (Fig. 8.3) represents uniform motion of a moving object correctly?
