Advertisements
Advertisements
प्रश्न
A train starting from rest moves with a uniform acceleration of 0.2 m/s2 for 5 minutes. Calculate the speed acquired and the distance travelled in this time.
Advertisements
उत्तर
We have to find the distance travelled as well as final velocity of the train. We have the following information given,
Initial velocity, (u) = 0 m/s
Acceleration for the entire journey, (a) = 0.2 m/s2
Time taken,
(t) = (5) (60) s
= 300 s
So, we can find the final velocity using the relation,
v = u + at
Therefore, final velocity of the train is,
v = 0 + (0.2)(300)
= 60 m/s
We can calculate the distance travelled by the train, using the 2nd equation of motion,
`s = ut + 1/2at^2`
Put the values in above equation to find the distance travelled,
`(s) = 0(300) + 1/2(0.2)(300)^2`
= (9000) m
= 9 km
APPEARS IN
संबंधित प्रश्न
Under what condition(s) is the magnitude of average velocity of an object equal to its average speed?
What does the odometer of an automobile measure?
Name the physical quantity obtained by dividing ‘Distance travelled’ by ‘Time taken’ to travel that distance.
In addition to speed, what else should we know to predict the position of a moving body ?
Bus X travels a distance of 360 km in 5 hours whereas bus Y travels a distance of 476 km in 7 hours. Which
bus travels faster ?
A tortoise moves a distance of 100 metres in 15 minutes. What is the average speed of tortoise in km/h ?
A motorcyclist drives from place A to B with a uniform speed of 30 km h-1 and returns from place B to A with a uniform speed of 20 km h-1. Find his average speed.
Express 15 m s-1 in km h-1.
Express the following in m s−1.
1 km h−1
