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प्रश्न
A substance has a critical angle of 45° for yellow light. What is the refractive index of the substance?
संख्यात्मक
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उत्तर
Given: Critical angle, C = 45°
To Find: Refractive index of the medium, μ
Formula: `μ = 1/sin C`
= `1/(sin 45°)`
= `1/(1/sqrt2)`
= `sqrt2`
≈ 1.414
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