Question

A substance has a critical angle of 45° for yellow light. What is the refractive index of the substance?

Answer 1

Given: Critical angle, C = 45°

To Find: Refractive index of the medium, μ

Formula: `μ = 1/sin C`

= `1/(sin 45°)`

= `1/(1/sqrt2)`

= `sqrt2`

≈ 1.414