मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान इयत्ता ११

A Simple Microscope is Rated 5 X for a Normal Relaxed Eye. What Will Be Its Magnifying Power for a Relaxed Farsighted Eye Whose Near Point is 40 Cm? - Physics

Advertisements
Advertisements

प्रश्न

A simple microscope is rated 5 X for a normal relaxed eye. What will be its magnifying power for a relaxed farsighted eye whose near point is 40 cm?

थोडक्यात उत्तर
Advertisements

उत्तर

For a simple microscope,
Magnification for a normal relaxed eye, m = 5
Least distant of distinct vision, D = 25 cm
Now,
Let the focal length be f.
The image will form at infinity, as the eye is relaxed.
The magnifying power  (m) of a simple microscope in normal adjustment is given by

`m =D/f`

`=> 5 = 25/f`

⇒ f= 5 cm

For the relaxed far-sighted eye, D = 40 cm.
Magnification (m):

`m=D/f =40/5 =8`

The magnifying power for a simple microscope is 8X.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 19: Optical Instruments - Exercise [पृष्ठ ४३२]

APPEARS IN

एचसी वर्मा Concepts of Physics Vol. 1 [English] Class 11 and 12
पाठ 19 Optical Instruments
Exercise | Q 5 | पृष्ठ ४३२

संबंधित प्रश्‍न

Explain the basic differences between the construction and working of a telescope and a microscope


A giant refracting telescope has an objective lens of focal length 15 m. If an eye piece of focal length 1.0 cm is used, what is the angular magnification of the telescope ?


The total magnification produced by a compound microscope is 20. The magnification produced by the eye piece is 5. The microscope is focussed on a certain object. The distance between the objective and eyepiece is observed to be 14 cm. If least distance of distinct vision is 20 cm, calculate the focal length of the objective and the eye piece.


A person with a normal near point (25 cm) using a compound microscope with the objective of focal length 8.0 mm and an eyepiece of focal length 2.5 cm can bring an object placed at 9.0 mm from the objective in sharp focus. What is the separation between the two lenses? Calculate the magnifying power of the microscope.


When are two objects just resolved? Explain.


Does the magnifying power of a microscope depend on the colour of the light used? Justify your answer.


How is 'limit of resolution' related to resolving power of a microscope ?


A compound microscope has an objective of focal length 1.25 cm and eyepiece of focal length 5 cm. A small object is kept at 2.5 cm from the objective. If the final image formed is at infinity, find the distance between the objective and the eyepiece ?


An object is placed at a distance u from a simple microscope of focal length f. The angular magnification obtained depends


The focal length of the objective of a compound microscope if fo and its distance from the eyepiece is L. The object is placed at a distance u from the objective. For proper working of the instrument,
(a) L < u
(b) L > u
(c) fo < < 2fo
(d) > 2fo


Consider the following two statements :-

(A) Line spectra contain information about atoms.

(B) Band spectra contain information about molecules.


Draw a neat labelled ray diagram showing the formation of an image at the least distance of distinct vision D by a simple microscope. When the final image is at D, derive an expression for its magnifying power at D. 


compound microscope consists of two convex lenses of focal length 2 cm and 5 cm. When an object is kept at a distance of 2.1 cm from the objective, a virtual and magnified image is fonned 25 cm from the eye piece.  Calculate the magnifying power of the microscope.


Define the magnifying power of a microscope in terms of visual angle.


A thin converging lens of focal length 5cm is used as a simple microscope. Calculate its magnifying power when image formed lies at:

  1. Infinity.
  2. Least distance of distinct vision (D = 25 cm).

The near vision of an average person is 25 cm. To view an object with an angular magnification of 10, what should be the power of the microscope?


A compound microscope consists of two converging lenses. One of them, of smaller aperture and smaller focal length, is called objective and the other of slightly larger aperture and slightly larger focal length is called eye-piece. Both lenses are fitted in a tube with an arrangement to vary the distance between them. A tiny object is placed in front of the objective at a distance slightly greater than its focal length. The objective produces the image of the object which acts as an object for the eye-piece. The eye-piece, in turn, produces the final magnified image.

The magnification due to a compound microscope does not depend upon ______.


The focal lengths of the objective and the eye-piece of a compound microscope are 1.0 cm and 2.5 cm respectively. Find the tube length of the microscope for obtaining a magnification of 300.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×