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A silver ornament of mass ‘m’ gram is polished with gold equivalent to 1% of the mass of silver. Compute the ratio of the number of atoms of gold and silver in the ornament. - Science

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प्रश्न

A silver ornament of mass ‘m’ gram is polished with gold equivalent to 1% of the mass of silver. Compute the ratio of the number of atoms of gold and silver in the ornament.

थोडक्यात उत्तर
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उत्तर

Mass of gold = mg

Mass of gold = `"m"/100`g

Number of atoms of silver = `"Mass"/"Atomic mass" xx "N"_"A"`

= `"m"/100 xx "N"_"A"`

Number of atoms of gold = `"m"/(100 xx 197) xx "N"_"A"`

Ratio of number of atoms of gold to silver = Au : Ag

= `"m"/(100 xx 197) xx "N"_"A" : "m"/108 xx "N"_"A"`

= 108 : 100 × 197

= 108 : 19700

= 1: 182.41

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पाठ 3: Atoms and Molecules [पृष्ठ २३]

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एनसीईआरटी एक्झांप्लर Science [English] Class 9
पाठ 3 Atoms and Molecules
Q 42. | पृष्ठ २३

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