Question

A rectangular field is 70 m long and 60 m broad. A well of dimensions 14 m × 8 m × 6 m is dug outside the field and the earth dug-out from this well is spread evenly on the field. How much will the earth level rise?

Answer 1

\[\text { Dimension of the well = 14 m } \times 8 m \times 6 m \]

\[\text { The volume of the dug - out earth = 14  }\times 8 \times 6 = 672 m^3 \]

\[\text { Now, we will spread this dug - out earth on a field whose length, breadth and height are 70 m, 60 m and h m, respectively } . \]

\[\text { Volume of the dug - out earth = length } \times \text { breadth }\times \text { height  }= 70 \times 60 \times h\]

\[ \Rightarrow 672 = 4200 \times h\]

\[ \Rightarrow h = \frac{672}{4200} = 0 . 16 m\]

\[\text { We know that 1 m = 100 cm }\]

\[ \therefore \text { The earth level will rise by 0 . 16 m = 0 . 16 } \times 100 cm = 16 cm .\]