Question

A pulley system with velocity ratio 5 can lift a load ‘L’ by an effort of 150 kgf. If the efficiency of system is 75%, calculate the value of L.

Answer 1

Given: Velocity ratio, VR = 5

Effort = 150 kgf

Efficiency = 75%

We know that efficiency, `eta = "Mechanical Advantage"/"Velocity Ratio"`

`75/100 = "MA"/5`

`MA = 5 xx 75/100`

∴ Mechanical advantage = 3.75

But, Mechanical advantage = `"Load (L)"/"Effort (E)"`

∴ Load  = Mechanical advantage × Effort

= 3.75 × 150 Kgf

= 562.5 Kgf