Advertisements
Advertisements
प्रश्न
A principal becomes ₹ 17,000 at the rate of 12% in 3 years. Find the principal.
Advertisements
उत्तर
Given the Principal becomes ₹ 17,000
Let the principle initially be P
Rate of Interest r = 12% per annum
Time n = 3 years
According to the problem given I = 17000 – P
= `("P" xx 3 xx 12)/100`
17000 = `36/100 "P" + "P"`
17000 = `"P"(36/100 + 1)`
17000 = `"P"(136/100)`
P = `(17000 xx 100)/136`
P = 12,500
∴ Principal P = ₹ 12,500
APPEARS IN
संबंधित प्रश्न
Rohit borrowed Rs. 24,000 at 7.5 percent per year. How much money will he pay at the end of the 4th years to clear his debt?
At what rate percent of simple interest will the interest on Rs.3750 be one-fifth of itself in 4 years? To what will it amount in 15 years?
Mahesh deposited rupees 8650 in a bank at a rate of 6 p.c.p.a. How much money will he get at the end of the year in all?
Given the principal = Rs 40,000, rate of interest = 8% p.a. compounded annually. Find
- Interest if period is one year.
- Principal for 2nd year.
- Interest for 2nd year.
- Amount if period is 2 years.
Interest on ₹ 12000 for 1 month at the rate of 10% per annum is ______.
Rajni and Mohini deposited ₹ 3000 and ₹ 4000 in a company at the rate of 10% per annum for 3 years and `2 1/2` years respectively. The difference of the amounts received by them will be ______.
Dhruvika invested money for a period from May 2006 to April 2008 at rate of 12% per annum. If interest received by her is ₹ 1620, find the money invested.
Bhavya earns ₹ 50,000 per month and spends 80% of it. Due to pay revision, her monthly income increases by 20% but due to price rise, she has to spend 20% more. Find her new savings.
Divide ₹ 10000 in two parts so that the simple interest on the first part for 4 years at 12 per cent per annum may be equal to the simple interest on the second part for 4.5 years at 16 per cent per annum.
The simple interest on a certain sum for 2.5 years at 12 per cent per annum is ₹ 300 less than the simple interest on the same sum for 4.5 years at 8 per cent per annum. Find the sum.
