Advertisements
Advertisements
प्रश्न
The value of a machine depreciates at 10% per year. If the present value is ₹ 1,62,000, what is the worth of the machine after two years?
Advertisements
उत्तर
Present value of the machine = ₹ 1,67,000
Rate of depreciation = 10% per annum
Time (n) = 2 years
For 1 year depreciation amount = `(1,62,000 xx 1 xx 10)/100` = ₹ 16,200
Worth of the machine after one year = Worth of Machine – Depreciation
= 1,67,000 – 16,200
= 1,45,800
Depreciation of the machine for 2nd year
= `145800 xx 1 xx 10/100` = 14580
Worth of the machine after 2 years
= 1,45,800 – 14,580
= 1,31,220
∴ Worth of the machine after 2 years = ₹ 1,31,220
APPEARS IN
संबंधित प्रश्न
Find the interest and the amount on:
₹ 4,000 in `1 1/3` years at 2 paise per rupee per month.
In how many years will Rs.950 produce Rs.399 as a simple interest at 7%?
The simple interest on a certain sum of money is `3/8` of the sum in `6 1/4` years. Find the rate percent charged.
Raj borrows Rs.8,000; out of which Rs. 4500 at 5% and the remainder at 6%. Find the total interest paid by him in 4 years.
Vinita deposited Rs. 15000 in a bank for one year at an interest rate of 7 p.c. p.a. How much interest will she get at the end of the year?
Given the principal = Rs 40,000, rate of interest = 8% p.a. compounded annually. Find principal for 2nd year.
Interest = `(P xx R xx T)/100`, where T is ______ R% is ______ and P is ______.
Interest on ₹ 1200 for `1 1/2` years at the rate of 15% per annum is ₹ 180.
Amount received after depositing ₹ 800 for a period of 3 years at the rate of 12% per annum is ₹ 896.
Divide ₹ 10000 in two parts so that the simple interest on the first part for 4 years at 12 per cent per annum may be equal to the simple interest on the second part for 4.5 years at 16 per cent per annum.
