Advertisements
Advertisements
प्रश्न
A pendulum oscillates 40 times in 4 seconds. Find its time period and frequency.
Advertisements
उत्तर
The frequency of oscillations is defined as the number of oscillations of a vibrating body per second. It is given by
Frequency = `"Number of Oscillations"/"Total Time"` = `40/4` = 10 Hz
The time required to complete one oscillation is known as the time period. It is given by the inverse of the frequency
Time period = `1/"Frequency of oscillation"` = `1/10` = 0.1 s
APPEARS IN
संबंधित प्रश्न
Name the phenomenon that causes a loud sound when the stem of a vibrating tuning fork is kept pressed on the surface of a table.
A person standing between two vertical cliffs and 480 m from the nearest cliff shouts. He hears the first echo after 3s and the second echo 2s later. Calculate:
1)The speed of sound.
2) The distance of the other cliff from the person
In a longitudinal wave, compression and rarefaction are formed.
Why is the loudness of sound heard by a plucked wire increased when mounted on a sound board?
The frequencies of notes given by flute, guitar and trumpet are respectively 400 Hz, 200 Hz and 500 Hz. Which one of these has the highest pitch?
Explain the following and illustrate your answer by drawing appropriate diagram:
Frequency
Name the factors which determine the pitch of a note.
A 0.6 m long stretched wire is made to vibrate in two different modes as shown in figure
(a)
(b)
(i) If the frequency of the note produced in (b) is n, what is the frequency in case (a)?
(ii) In which case (a) or (b), is the note louder? Give reasons.
(iii) In which case is the pitch higher? Give reason.
If ______ of sound is decreased, its loudness also decreases.
Give scientific reason.
In earlier times, people used to listen for the arrival of a distant train by putting their ear to the rail.
