मराठी

A pendulum has a frequency of 5 vibrations per second. An observer starts the pendulum and fires a gun simultaneously. He hears echo from the cliff after 8 vibrations of the pendulum. If the velocity - Physics

Advertisements
Advertisements

प्रश्न

A pendulum has a frequency of 5 vibrations per second. An observer starts the pendulum and fires a gun simultaneously. He hears echo from the cliff after 8 vibrations of the pendulum. If the velocity of sound in air is 340 ms−1, find the distance between the cliff and the observer.

संख्यात्मक
Advertisements

उत्तर

Speed of sound in air v = 340 m/s−1

Time taken for 8 vibration t = `8/5` sec

The distance between the cliff and the observer:

d = `(vt)/2`

= `(340 xx 8)/(2 xx 5)`

= 272 m

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Sound - EXERCISE - 7 (A) [पृष्ठ १५५]

APPEARS IN

सेलिना Physics [English] Class 10 ICSE
पाठ 7 Sound
EXERCISE - 7 (A) | Q 8. | पृष्ठ १५५
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×