Advertisements
Advertisements
प्रश्न
A pendulum has a frequency of 5 vibrations per second. An observer starts the pendulum and fires a gun simultaneously. He hears echo from the cliff after 8 vibrations of the pendulum. If the velocity of sound in air is 340 ms−1, find the distance between the cliff and the observer.
संख्यात्मक
Advertisements
उत्तर
Speed of sound in air v = 340 m/s−1
Time taken for 8 vibration t = `8/5` sec
The distance between the cliff and the observer:
d = `(vt)/2`
= `(340 xx 8)/(2 xx 5)`
= 272 m
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
