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A Metre Stick is Held Vertically with One End on a Rough Horizontal Floor. It is Gently Allowed to Fall on the Floor.

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प्रश्न

A metre stick is held vertically with one end on a rough horizontal floor. It is gently allowed to fall on the floor. Assuming that the end at the floor does not slip, find the angular speed of the rod when it hits the floor.

बेरीज
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उत्तर

Let the mass of the rod and its angular velocity be m and ​ω (when hits the ground), respectively.

It is given that the rod has rotational motion only.

On applying the law of conservation of energy, we get

\[\frac{1}{2}I \omega^2  = mg\frac{l}{2}\]

\[ \Rightarrow \frac{m l^2}{3} \times  \omega^2  = mgl\]

\[ \Rightarrow  \omega^2  = \frac{3g}{l}\]

\[ \Rightarrow \omega =   \sqrt{\frac{3g}{l}} =   \sqrt{\left( 3 \times \frac{9 . 8}{1} \right)}\]

\[ \Rightarrow \omega =   5 . 42\text{ rad/s}\]

 

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Momentum Conservation and Centre of Mass Motion
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पाठ 10: Rotational Mechanics - Exercise [पृष्ठ १९९]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
पाठ 10 Rotational Mechanics
Exercise | Q 67 | पृष्ठ १९९

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