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प्रश्न
A man walks 1 km towards the East and then he turns to the South and walks 5 km. Again he turns East and walks 2 km, after this, he turns North and walks 9 km. Now, how far is he from his starting point?
पर्याय
3 km
4 km
5 km
7 km
MCQ
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उत्तर
5 km
Explanation:
The movements of the man are as shown in the given below (A to B, B to C, C to D, D to E).
Clearly, CF = BC = 5 km.
EF = (DE - DF) = (9 - 5) km = 4 km.
BF = CD = 2 km
AF = AB + BF = AB + CD (1 + 2) km = 3 km.
∴ Man's distance from starting point A
= AE = `sqrt("AF"^2 + "EF"^2)`
= `sqrt(3^2 + 4^2 = sqrt25) = 5` km
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