Question

A man walks 1 km towards the East and then he turns to the South and walks 5 km. Again he turns East and walks 2 km, after this, he turns North and walks 9 km. Now, how far is he from his starting point?

विकल्प

• 3 km

• 4 km

• 5 km

• 7 km

Answer 1

5 km

Explanation:

The movements of the man are as shown in the given below (A to B, B to C, C to D, D to E).

Clearly, CF = BC = 5 km.

EF = (DE - DF) = (9 - 5) km = 4 km.

BF = CD = 2 km

AF = AB + BF = AB + CD (1 + 2) km = 3 km.

∴ Man's distance from starting point A

= AE = `sqrt("AF"^2 + "EF"^2)`

= `sqrt(3^2 + 4^2 = sqrt25) = 5` km