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प्रश्न
A man applies the effort of 150 N on one end of a fixed pulley to pull a bucket of water of mass 12 kg. What is the force of friction, mechanical advantage and efficiency of this pulley?
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उत्तर
Given:
Effort (E) = 150 N
Mass of the bucket (m) = 12 kg
Acceleration due to gravity (g) = 10 m/s2
Load (L) = m × g
= 12 × 10
= 120 N
For a single fixed pulley, the standard Velocity Ratio (VR) is always 1.
(i) In a single fixed pulley with friction, the effort applied must overcome both the load and the frictional force:
E = L + f
150 = 120 + f
f = 150 − 120
f = 30 N
(ii) Mechanical Advantage (MA) = `"Load (L)"/"Effort (E)"`
= `120/150`
= 0.8
(iii) Efficiency (η) = `(MA)/(VR) xx 100%`
= `0.8/1 xx 100%`
= 80%
The force of friction is 30 N, the mechanical advantage is 0.8, and the efficiency is 80%.
