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प्रश्न
A machine uplifts a load of 100 N by 10 cm. In this process, it requires 80 N of effort with downward displacement of 15 cm. Calculate:
- mechanical advantage
- velocity ratio
- work input
- efficiency of the machine
संख्यात्मक
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उत्तर
Given:
Load (L) = 100 N
Distance moved by load (dL) = 10 cm = 0.1 m
Effort (E) = 80 N
Distance moved by effort (dE) = 15 cm = 0.15 m
(i) Mechanical Advantage (MA) = `"Load (L)"/"Effort (E)"`
= `100/80`
= 1.25
(ii) Velocity Ratio (VR) = `("Distance moved by Effort" (d_E))/("Distance moved by Load" (d_L))`
= `15/10`
= 1.5
(iii) Work Input = Effort (E) × Distance moved by Effort (dE in meters)
= 80 × 0.15
= 12 J
(iv) Efficiency of the machine (η) = `(MA)/(VR) xx 100%`
= `1.25/1.5 xx 100%`
= 0.8333 × 100%
= 83.33%
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