Question

A line passes through P(1, 2) such that its intercept between the axes is bisected at P. The equation of the line is ______.

पर्याय

• x + 2y = 5

• x – y + 1 = 0

• x + y – 3 = 0

• 2x + y – 4 = 0

Answer 1

A line passes through P(1, 2) such that its intercept between the axes is bisected at P. The equation of the line is 2x + y – 4 = 0.

Explanation:

We know that the equation of a line making intercepts a and b with x-axis and y-axis, respectively, is given by

`x/a + y/b` = 1.

Here we have 1 = `(a + 0)/2` and 2 = `(0 + b)/2`.

Which give a = 2 and b = 4.

Therefore, the required equation of the line is given by

`x/2 + y/4` = 1 or 2x + y – 4 = 0