Question

A light wave is incident normally on a glass slab of refractive index 1.5. If 10% of light gets reflected and the amplitude of the electric field of the incident light is `30 V/m`, then the amplitude of the electric field for the wave propagating in the glass medium will be:

पर्याय

• `10 V/m`

• `24 V/m`

• `30 V/m`

• `6 V/m`

Answer 1

`bb(24 V/m)`

Explanation:

Percentage of refracted light:

`P_"refracted" = 96/100 P_I`

Thus, `n_2A_t^2 = 96/100 n_1A_i^2`

Here n₁ = 1, n₂ = 1.5 = `3/2`

Or `A_t^2 = 96/100 xx 2/3 xx (30)^2`

= `192/300 xx 900`

= 0.64 × 900

= 576

= `sqrt576`

A_t = 24